Count the number of odd and even digits

Problem statement:- Program to Find the number of odd and even digits in the given number.

Sample Input/Output:-

Sample Input First: 879413                  Sample Output First: 2  4

Sample Input Second: 547863             Sample Output Second: 3  3

Data requirement:-

   Input Data:- num

  Output Data:-even, odd

Program in C

Here is the source code of the C Program to Find the number of odd and even digits in the given number.

Code:

#include<stdio.h>

int main()

{

    int num;

    printf("Enter the number:");

    scanf("%d",&num);

    int odd=0,even=0;

    while(num!=0)

    {

        int rem=num%10;

        if(rem%2==1)

            odd++;

        else

            even++;

        num/=10;

    }

    printf("Number of even digits = %d\n",even);

    printf("Number of odd digits = %d",odd);

}

Input/Output:

Enter the number:879413

Number of even digits = 2

Number of odd digits = 4

Program in C++

Here is the source code of the C++ Program to count the number of odd and even digits in an integer.

Code:

#include<iostream>

using namespace std;

int main()

{

    int num;

    cout<<"Enter the number:";

    cin>>num;

    int odd=0,even=0;

    while(num!=0)

    {

        int rem=num%10;

        if(rem%2==1)

            odd++;

        else

            even++;

        num/=10;

    }

    cout<<"Number of even digits = "<<even;

    cout<<"Number of odd digits = "<<odd;

}

Input/Output:

Enter the number:547863

Number of even digits = 3

Number of odd digits = 3

Program in Java

Here is the source code of the Java Program to Find the number of odd and even digits in the given number.

Code:

import java.util.Scanner;

public class NumberOfOddAndEvenDigits {

public static void main(String[] args) {

    Scanner cs=new Scanner(System.in);

    int num;

    System.out.println("Enter the number:");

    num=cs.nextInt();

    int odd=0,even=0;

    while(num!=0)

    {

        int rem=num%10;

        if(rem%2==1)

            odd++;

        else

            even++;

        num/=10;

    }

    System.out.println("Number of even digits = "+even);

    System.out.println("Number of odd digits = "+odd);

    cs.close();

}

}

Input/Output:

Enter the number:

535254456

Number of even digits = 4

Number of odd digits = 5

Program in Python

Here is the source code of the Python Program to count the number of odd and even digits in an integer.

Code:

print("Enter the number:")
num=int(input())
odd=0
even=0
while(num!=0):
    rem=num%10
    if(rem%2==1):
        odd+=1
    else:
        even+=1
    num//=10
print("Number of even digits = ",even)
print("Number of odd digits = ",odd) 

Input/Output:

Enter the number:

5432

Number of even digits =  2

Number of odd digits =  2

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