# Count the number of odd and even digits

Problem statement:- Program to Find the number of odd and even digits in the given number.

#### Sample Input/Output:-

Sample Input First: 879413                  Sample Output First: 2  4

Sample Input Second: 547863             Sample Output Second3  3

#### Data requirement:-

Input Data:- num

Output Data:-
even, odd

Program in C

### Here is the source code of the C Program to Find the number of odd and even digits in the given number.

Code:

#include<stdio.h>
int main()
{
int num;
printf("Enter the number:");
scanf("%d",&num);
int odd=0,even=0;
while(num!=0)
{
int rem=num%10;
if(rem%2==1)
odd++;
else
even++;
num/=10;
}
printf("Number of even digits = %d\n",even);
printf("Number of odd digits = %d",odd);
}

Input/Output:
Enter the number:879413
Number of even digits = 2
Number of odd digits = 4

Program in C++

### Here is the source code of the C++ Program to count the number of odd and even digits in an integer.

Code:

#include<iostream>
using namespace std;
int main()
{
int num;
cout<<"Enter the number:";
cin>>num;
int odd=0,even=0;
while(num!=0)
{
int rem=num%10;
if(rem%2==1)
odd++;
else
even++;
num/=10;
}
cout<<"Number of even digits = "<<even;
cout<<"Number of odd digits = "<<odd;
}

Input/Output:
Enter the number:547863
Number of even digits = 3
Number of odd digits = 3

Program in Java

### Here is the source code of the Java Program to Find the number of odd and even digits in the given number.

Code:

import java.util.Scanner;
public class NumberOfOddAndEvenDigits {

public static void main(String[] args) {
Scanner cs=new Scanner(System.in);
int num;
System.out.println("Enter the number:");
num=cs.nextInt();
int odd=0,even=0;
while(num!=0)
{
int rem=num%10;
if(rem%2==1)
odd++;
else
even++;
num/=10;
}
System.out.println("Number of even digits = "+even);
System.out.println("Number of odd digits = "+odd);
cs.close();
}
}

Input/Output:
Enter the number:
535254456
Number of even digits = 4
Number of odd digits = 5

Program in Python

### Here is the source code of the Python Program to count the number of odd and even digits in an integer.

Code:

print("Enter the number:")
num=int(input())
odd=0
even=0
while(num!=0):
rem=num%10
if(rem%2==1):
odd+=1
else:
even+=1
num//=10
print("Number of even digits = ",even)
print("Number of odd digits = ",odd)

Input/Output:
Enter the number:
5432
Number of even digits =  2
Number of odd digits =  2