Program to compute the area and perimeter of Rhombus

Problem statement:-  Program to compute the area and perimeter of the Rhombus.

Formula:

Area Of Rhombus(A):

A

=

p×

q

2

where p and q =Diagonals length of the Rhombus

Perimeter of Rhombus(P):

P

 

=

 

4a

 Data requirement:-

   Input Data:- a, p, q

  Output Data:- area, perimeter

Program in C

Here is the source code of the C Program to compute the area and perimeter of the Rhombus.

Code:

#include<stdio.h>
int main()
{
    printf("Enter the two Diagonals Value:");
    int p,q,a;
    scanf("%d%d",&p,&q);
    printf("Enter the length of the side value:");
    scanf("%d",&a);
    double area=(p*q)/2.0;
    int perimeter=(4*a);
    printf("Area of the Rhombus = %0.2lf\n",area);
    printf("Perimeter of the Rhombus = %d",perimeter);
}

Input/Output:

Enter the two Diagonals Value:7
6
Enter the length of the side value:5
Area of the Rhombus = 21.00
Perimeter of the Rhombus = 20

Program in C++

Here is the source code of the C++ Program to compute the area and perimeter of the Rhombus.

Code:

#include<iostream>
using namespace std;
int main()
{
    cout<<"Enter the two Diagonals Value:";
    int p,q,a;
    cin>>p;
    cin>>q;
    cout<<"Enter the length of the side value:";
    cin>>a;
    double area=(p*q)/2.0;
    int perimeter=(4*a);
    cout<<"Area of the Rhombus = "<<area;
    cout<<"\nPerimeter of the Rhombus = "<<perimeter;
}

Input/Output:

Enter the two Diagonals Value:7
9
Enter the length of the side value:10
Area of the Rhombus = 31.5
Perimeter of the Rhombus = 40

Program in Java

  

Here is the source code of the Java Program to compute the area and perimeter of the Rhombus.

Code:

import java.util.Scanner;
public class Area_Perimeter_Rhombus {

public static void main(String[] args) {
Scanner cs=new Scanner(System.in);
System.out.println("Enter the two Diagonals Value:");
    int p,q,a;
    p=cs.nextInt();
    q=cs.nextInt();
    System.out.println("Enter the length of the side value:");
    a=cs.nextInt();
    double area=(p*q)/2.0;
    int perimeter=(4*a);
    System.out.println("Area of the Rhombus = "+area);
    System.out.println("Perimeter of the Rhombus = "+perimeter);
    cs.close();
}
}

Input/Output:

Enter the two Diagonals Value:
5
8
Enter the length of the side value:
4
Area of the Rhombus = 20.0
Perimeter of the Rhombus = 16

Program in Python
  

Here is the source code of the Python Program to compute the area and perimeter of the Rhombus.

Code:

print("Enter the two Diagonals Value:")
p=int(input())
q=int(input())
a=int(input("Enter the length of the side value:"))
area=(p*q)/2.0
perimeter=(4*a)
print("Area of the Rhombus = ",area)
print("Perimeter of the Rhombus = ",perimeter)

Input/Output:

Enter the two Diagonals Value:
10
12
Enter the length of the side value:20
Area of the Rhombus =  60.0
Perimeter of the Rhombus =  80

Most Recommend Questions:-

• Write a Program to compute the area and perimeter of the Hexagon.

• Write a Program to compute the area and perimeter of the Heptagon.
  

• Write a Program to Calculate the surface area and volume of a sphere.
  

•  Write a Program to Calculate the surface area and volume of a Hemisphere.

• Write a Program to Calculate the surface area and volume of a cone.

More Questions:-

Basic Programming problem and solution

C/C++/Java/Python Practice Question