Program to Find nth Armstrong Number

A Number is an Armstrong Number if the sum of cubes of digits of the number is equal to Given Number.

Example:

               Given Number=370
               sum of cubes of digits=3³+7³+0³=27+343+0=370
              
                             
Problem statement:-  Program to Find nth Armstrong Number.

Data requirement:-

   Input Data:- rangenumber

   Output Data:- rangenumber, letest

   Additional Data:- cnum, num1, sum, rem

Program in C

Here is the source code of the C Program to Find nth Armstrong Number.

Code:

//Write a Program to Find nth Armstrong Number.
#include <stdio.h>
int
main ()
{
  int i, rangenumber, num = 1, c = 0, letest = 0;
  printf ("Enter the Nth value:");
  scanf ("%d", &rangenumber);

  while (c != rangenumber)
    {
        int num2=num;
        int num1=num;
        int sum=0;
    //reverse of number
    while(num1!=0)
    {
       int rem=num1%10;
       num1=num1/10;
       sum=sum+rem*rem*rem;//(sum+=pow(rem,3))
    }
   if(sum==num2)
    {
          c++;
          letest=num;
    }
      num = num + 1;
    }
  printf ("%dth Armstrong number is %d", rangenumber, letest);
  return 0;
}

Input/Output:
Enter the Nth value:3
3th Armstrong number is 370

Program in C++

Here is the source code of the C++ Program to Find nth Armstrong Number.

Code:

#include <iostream>
using namespace std;
int
main ()
{
  int i, rangenumber, num = 1, c = 0, letest = 0;
  cout<<"Enter the Nth value:";
  cin>>rangenumber;

  while (c != rangenumber)
    {
      int num2=num;
        int num1=num;
        int sum=0;
    while(num1!=0)
    {
       int rem=num1%10;
       num1=num1/10;
       sum=sum+rem*rem*rem;
    }
   if(sum==num2)
    {
          c++;
          letest=num;
      }
      num = num + 1;
    }
  cout<<rangenumber<<"th Armstrong number is "<<letest;
  return 0;
}

Input/Output:
Enter the Nth value:5
5th Armstrong number is 407

Program in Java
  
Here is the source code of the Java Program to Find nth Armstrong Number.

Code:

import java.util.Scanner;
public class NthArmstrongNumber {

public static void main(String[] args) {
Scanner cs=new Scanner(System.in);
int  rangenumber, num = 1, c = 0, letest = 0;
  System.out.println("Enter Nth number:");
  rangenumber=cs.nextInt();

  while (c != rangenumber)
    {
      int num2 = num;
      int num1 = num;
      int sum = 0;
      while (num1 != 0)
{
  int rem = num1 % 10;
  num1 = num1 / 10;
  sum = sum + rem * rem * rem;
}
      if (sum == num2)
{
  c++;
  letest = num;
}
      num = num + 1;
    }

System.out.println(rangenumber+"th Armstrong number is "+letest);
cs.close();
}
}

Input/Output:
Enter Nth number:
2
2th Armstrong number is 153

Program in Python
  
Here is the source code of the Python Program to Find nth Armstrong Number.

Code:

rangenumber=int(input("Enter a Nth Number:"))
c = 0
letest = 0
num = 1
while c != rangenumber:
    num2 = num
    num1 = num
    sum = 0
    while num1 != 0:
        rem = num1 % 10
        num1 = num1 // 10
        sum = sum + rem * rem * rem
    if sum == num2:
        c+=1
        letest = num

    num = num + 1
print(rangenumber,"th Armstrong Number is ",latest)

Input/Output:
Enter a Nth Number:4
4 th Armstrong Number is  371


More:-

C/C++/Java/Python Practice Question 

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