Check whether number is Sunny Number or Not.

A Number is a Sunny number if 1 is added to that number and the square root of it becomes a whole number.

Example:

               Given Number=8
               (8+1)=9 square root of 9 =3(it is a whole number )
               so, 8 is Sunny Number.
                 
                Given Number=6
               (6+1)=7 square root of 7 =2.65(it is not a whole number )
               so, 8 is not a Sunny Number.
                                          
Problem statement:-  Program to check whether the number is Sunny Number or Not.

Data requirement:-

   Input Data:- num

   Output Data:- String output

   Additional Data:- root

Program in C

Here is the source code of the C Program to check whether the number is Sunny Number or Not.

Code:

//Sunny Number Or Not
#include<stdio.h>
#include<math.h>
int main()
{
    int num;
    printf("Enter the number:");
    scanf("%d",&num);
    double root;
    root=sqrt(num+1);
   if((int)root==root)
    printf("It is a Sunny Number.");
   else
    printf("It is not a Sunny Number.");
}

Input/Output:

Enter the number:8
It is a Sunny Number.

Program in C++

Here is the source code of the C++ Program to check whether the number is Sunny Number or Not.

Code:

#include <iostream>
#include<cmath>
using namespace std;
int main()
{
    int num,i;
    cout<<"Enter the number:";
    cin>>num;

     double root;
    root=sqrt(num+1);
   if((int)root==root)
    cout<<"It is a Sunny Number.";
   else
    cout<<"It is not a Sunny Number.";
}

Input/Output:

Enter the number:6
It is not a Sunny Number.

Program in Java

  

Here is the source code of the Java Program to check whether the number is Sunny Number or Not.

Code:

import java.util.Scanner;
public class SunnyNumberOrNot {

public static void main(String[] args) {
Scanner cs=new Scanner(System.in);
     int num;
     System.out.println("Enter a number:");
     num=cs.nextInt();
     double root;
     root=Math.sqrt(num+1);
    if((int)root==root)
      System.out.println("It is a Sunny Number.");
    else
         System.out.println("It is not a Sunny Number.");
  cs.close();
}
}

Input/Output:

Enter a number:
48
It is a Sunny Number.

Program in Python
  

Here is the source code of the Program to check whether the number is Sunny Number or Not.

Code:

import math
num=int(input("Enter a number:"))
root=math.sqrt(num+1)
if int(root)==root:
    print("It is a Sunny Number.")
else:
   print("It is Not a Sunny Number.")

Input/Output:

Enter a number:30
It is Not a Sunny Number.

More:-

C/C++/Java/Python Practice Question