Check whether number is Pronic Number or Not

A Number is a Pronic number which is the product of two consecutive integers, that is, a number of the form num(num+1).

Example:

               Given Number=90
               product of two consecutive number 9*10=90
               so, 90 is a Pronic Number.
                 
                Given Number=80
               there are no consecutive multiple presents. 
               That's why 80 is not a  Pronic Number.
                                          
Problem statement:-  Program to check whether the number is Pronic Number or Not.

Data requirement:-

   Input Data:- num

   Output Data:- String output

   Additional Data:- root

Program in C

Here is the source code of the C Program to check whether the number is Pronic Number or Not.

Code:

//Pronic Number Or Not
#include<stdio.h>
int main()
{
    int num;
    printf("Enter the number:");
    scanf("%d",&num);
   int flag=0,i;
   for(i=0;i<=num;i++)
   {
       if(i*(i+1)==num)
       {
           flag=1;
           break;
       }
   }

   if(flag==1)
    printf("It is a Pronic Number.");
   else
    printf("It is not a Pronic Number.");
}

Input/Output:
Enter the number:90
It is a Pronic Number.

Program in C++

Here is the source code of the C++ Program to check whether the number is a Pronic Number or Not.

Code:

#include <iostream>
using namespace std;
int main()
{
    int num,i;
    cout<<"Enter the number:";
    cin>>num;
    int flag=0;
   for(i=0;i<=num;i++)
   {
       if(i*(i+1)==num)
       {
           flag=1;
           break;
       }
   }

   if(flag==1)
    cout<<"It is a Pronic Number.";
   else
    cout<<"It is not a Pronic Number.";
}

Input/Output:
Enter the number:80
It is not a Pronic Number.

Program in Java
  
Here is the source code of the Java Program to check whether the number is a Pronic Number or Not.

Code:

import java.util.Scanner;
public class PronicNumberOrNot {

public static void main(String[] args) {
Scanner cs=new Scanner(System.in);
     int num;
     System.out.println("Enter a number:");
     num=cs.nextInt();
     int flag=0,i;
     for(i=0;i<=num;i++)
     {
         if(i*(i+1)==num)
         {
             flag=1;
             break;
         }
     }

     if(flag==1)
        System.out.println("It is a Pronic Number.");
    else
         System.out.println("It is not a Pronic Number.");
  cs.close();
}
}

Input/Output:
Enter a number:
72
It is a Pronic Number.

Program in Python
  
Here is the source code of the Program to check whether the number is Pronic Number or Not.

Code:

import math
num=int(input("Enter a number:"))
flag=0
for i in range(0,num+1):
    if i*(i+1)==num:
        flag=1
        break
if flag==1:
    print("It is a Pronic Number.")
else:
   print("It is Not a Pronic Number.")

Input/Output:
Enter a number:302
It is Not a Pronic Number.

More:-

C/C++/Java/Python Practice Question 

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