Problem statement:- Program to find the sum of series 1+X+X^3...+X^N
Data requirement:-
Input Data:- n, x
Output Data:- sum
Additional Data:- i
Program in C
Here is the source code of the C Program to find the sum of series 1+X+X^3...+X^N.
Code:
#include<stdio.h>
#include<math.h>
int main()
{
int n,sum=0,i=1,x;
printf("Enter the range of number:");
scanf("%d",&n);
printf("Enter the value of x:");
scanf("%d",&x);
while(i<=n)
{
sum+=pow(x,i);
i+=2;
}
printf("The sum of the series = %d",sum);
}
#include<math.h>
int main()
{
int n,sum=0,i=1,x;
printf("Enter the range of number:");
scanf("%d",&n);
printf("Enter the value of x:");
scanf("%d",&x);
while(i<=n)
{
sum+=pow(x,i);
i+=2;
}
printf("The sum of the series = %d",sum);
}
Input/Output:
Enter the range of number:5
Enter the value of x:2
The sum of the series = 42
Program in C++
Enter the value of x:2
The sum of the series = 42
Program in C++
Here is the source code of the C Program to find the sum of series 1+X+X^3...+X^N.
Code:
#include<iostream>
#include<cmath>
using namespace std;
int main()
{
int n,sum=0,i=1,x;
cout<<"Enter the range of number:";
cin>>n;
cout<<"Enter the value of x:";
cin>>x;
while(i<=n)
{
sum+=pow(x,i);
i+=2;
}
cout<<"The sum of the series = "<<sum;
}
#include<cmath>
using namespace std;
int main()
{
int n,sum=0,i=1,x;
cout<<"Enter the range of number:";
cin>>n;
cout<<"Enter the value of x:";
cin>>x;
while(i<=n)
{
sum+=pow(x,i);
i+=2;
}
cout<<"The sum of the series = "<<sum;
}
Input/Output:
Enter the range of number:8
Enter the value of x:4
The sum of the series = 17476
Enter the value of x:4
The sum of the series = 17476
Program in Java
Here is the source code of the Java Program to find the sum of series 1+X+X^3...+X^N.
Code:
import java.util.Scanner;
public class p6 {
public static void main(String[] args) {public class p6 {
Scanner cs=new Scanner(System.in);
int n,sum=0,i=1,x;
System.out.println("Enter the range of number:");
n=cs.nextInt();
System.out.println("Enter the value of x:");
x=cs.nextInt();
while(i<=n)
{
sum+=Math.pow(x,i);
i+=2;
}
System.out.println("The sum of the series = "+sum);
cs.close();
}
}
Enter the range of number:
3
Enter the value of x:
5
The sum of the series = 130
3
Enter the value of x:
5
The sum of the series = 130
Program in Python
Here is the source code of the Python Program to find the sum of series 1+X+X^3...+X^N.
Code:
print("Enter the range of number:")
n=int(input())print("Enter the value of x:");
x=int(input())
sum=0
i=1
while(i<=n):
sum+=pow(x,i)
i+=2
print("The sum of the series = ",sum)
Input/Output:
Enter the range of number:
9
Enter the value of x:
2
The sum of the series = 682
9
Enter the value of x:
2
The sum of the series = 682
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1 Comments
please correct the code in place of sum we have to put the sum=1
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