Problem Statement:- Program to find the sum of series 1^1/1+2^2/2+3^3/3...+n^n/n.
Data requirement:-
Input Data:- n
Output Data:-Sum
Additional Data:-i
Program in C
Here is the source code of the C Program to find the sum of series 1^1/1+2^2/2+3^3/3...+ n^n/n.
Code:
#include<stdio.h>
#include<math.h>
int main()
{
int n,i;
double sum=0.0;
printf("Enter the range of number:");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
sum+=pow(i,i)/i;
}
printf("The sum of the series = %0.2lf",sum);
}
#include<math.h>
int main()
{
int n,i;
double sum=0.0;
printf("Enter the range of number:");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
sum+=pow(i,i)/i;
}
printf("The sum of the series = %0.2lf",sum);
}
Input/Output:
Enter the range of number:5
The sum of the series = 701.00
Program in C++
The sum of the series = 701.00
Program in C++
Here is the source code of the C++ Program to find the sum of series 1^1/1+2^2/2+3^3/3...+ n^n/n.
Code:
#include<iostream>
#include<cmath>
using namespace std;
int main()
{
int n,i;
double sum=0.0;
cout<<"Enter the range of number:";
cin>>n;
for(i=1;i<=n;i++)
{
sum+=pow(i,i)/i;
}
cout<<"The sum of the series = "<<sum;
}
#include<cmath>
using namespace std;
int main()
{
int n,i;
double sum=0.0;
cout<<"Enter the range of number:";
cin>>n;
for(i=1;i<=n;i++)
{
sum+=pow(i,i)/i;
}
cout<<"The sum of the series = "<<sum;
}
Input/Output:
Enter the range of number:11
The sum of the series = 2.69827e+010
Program in Java
The sum of the series = 2.69827e+010
Program in Java
Here is the source code of the Java Program to find the sum of series 1^1/1+2^2/2+3^3/3... +n^n/n.
Code:
import java.util.Scanner;
public class p19 {
public static void main(String[] args) {
Scanner cs=new Scanner(System.in);
int n,i;
double sum=0.0;
System.out.println("Enter the range of number:");
n=cs.nextInt();
for(i=1;i<=n;i++){
sum+=Math.pow(i,i)/i;
}
System.out.println("The sum of the series = "+sum);
cs.close();
}
}
public class p19 {
public static void main(String[] args) {
Scanner cs=new Scanner(System.in);
int n,i;
double sum=0.0;
System.out.println("Enter the range of number:");
n=cs.nextInt();
for(i=1;i<=n;i++){
sum+=Math.pow(i,i)/i;
}
System.out.println("The sum of the series = "+sum);
cs.close();
}
}
Input/Output:
Enter the range of number:
7
The sum of the series = 126126.0
Program in Python
7
The sum of the series = 126126.0
Here is the source code of the Python Program to find the sum of series 1^1/1+2^2/2+3^3/3 ...+n^n/n.
Code:
import math
print("Enter the range of number:")
n=int(input())
sum=0.0
fact=1
for i in range(1,n+1):
sum += pow(i, i) / i
print("The sum of the series = ",sum)
print("Enter the range of number:")
n=int(input())
sum=0.0
fact=1
for i in range(1,n+1):
sum += pow(i, i) / i
print("The sum of the series = ",sum)
Input/Output:
Enter the range of number:
10
The sum of the series = 1045269999.0
10
The sum of the series = 1045269999.0
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