Problem statement:- Program to Find the sum of series 1-2+3-4+5-6...+N.
Data requirement:-
Input Data:- n
Output Data:-Sum
Additional Data:- i
Program in C
Input Data:- n
Output Data:-Sum
Additional Data:- i
Program in C
Here is the source code of the C Program to Find the sum of series 1-2+3-4+5-6...+N.
Code:
#include<stdio.h>
int main()
{
int n;
int sum=0,i;
printf("Enter the range of number:");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
if(i%2==0)
sum-=i;
else
sum+=i;
}
printf("The sum of the series = %d",sum);
}
Enter the range of number:6
The sum of the series = -3
Program in C++
Here is the source code of the C++ Program to Find the sum of series 1-2+3-4+5-6...+N.
Code:
#include<iostream>
using namespace std;
int main()
{
int n;
int sum=0,i;
cout<<"Enter the range of number:";
cin>>n;
for(i=1;i<=n;i++)
{
if(i%2==0)
sum-=i;
else
sum+=i;
}
cout<<"The sum of the series = "<<sum;
}
Enter the range of number:4
The sum of the series = -2
Program in Java
Here is the source code of the Java Program to Find the sum of series 1-2+3-4+5-6...+N.
Code:
import java.util.Scanner;
public class Sum_Of_Series2 {
public static void main(String[] args) {
Scanner cs=new Scanner(System.in);
int n;
int sum=0,i;
System.out.println("Enter the range of number:");
n=cs.nextInt();
for(i=1;i<=n;i++)
{
if(i%2==0)
sum-=i;
else
sum+=i;
}
System.out.println("The sum of the series = "+sum);
cs.close();
}
}
Enter the range of number:
8
The sum of the series = -4
Program in Python
Here is the source code of the Python Program to Find the sum of series 1-2+3-4+5-6...+N.
Code:
n=int(input("Enter the range of number:"))
sum=0
for i in range(1,n+1):
if i % 2 == 0:
sum -= i
else:
sum += i
print("The sum of the series = ",sum)
Enter the range of number:12
The sum of the series = -6
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