Problem statement:- Program to find the sum of series 1/2-2/3+3/4-4/5+5/6...+N/N+1
Data requirement:-
Input Data:- n
Output Data:-Sum
Additional Data:-i
Program in C
Input/Output:
Input/Output:
Input/Output:
Code:
Input/Output:
Data requirement:-
Input Data:- n
Output Data:-Sum
Additional Data:-i
Program in C
Here is the source code of the C Program to find the sum of series 1/2-2/3+3/4-4/5+5/6 ...+N/N+1.
Code:
#include<stdio.h>
int main()
{
int n;
double sum=0.0,i;
printf("Enter the range of number:");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
if((int)i%2==0)
sum-=i/(i+1);
else
sum+=i/(i+1);
}
printf("The sum of the series = %0.2lf",sum);
}
int main()
{
int n;
double sum=0.0,i;
printf("Enter the range of number:");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
if((int)i%2==0)
sum-=i/(i+1);
else
sum+=i/(i+1);
}
printf("The sum of the series = %0.2lf",sum);
}
Input/Output:
Enter the range of number:3
The sum of the series = 0.58
Program in C++
The sum of the series = 0.58
Program in C++
Here is the source code of the C++ Program to find the sum of series 1/2-2/3+3/4-4/5+5/6 ...+N/N+1.
Code:
#include<iostream>
#include<cmath>
using namespace std;
int main()
{
int n;
double sum=0.0,i;
cout<<"Enter the range of number:";
cin>>n;
for(i=1;i<=n;i++)
{
if((int)i%2==0)
sum-=i/(i+1);
else
sum+=i/(i+1);
}
cout<<"The sum of the series = "<<sum;
}
#include<cmath>
using namespace std;
int main()
{
int n;
double sum=0.0,i;
cout<<"Enter the range of number:";
cin>>n;
for(i=1;i<=n;i++)
{
if((int)i%2==0)
sum-=i/(i+1);
else
sum+=i/(i+1);
}
cout<<"The sum of the series = "<<sum;
}
Input/Output:
Enter the range of number:5
The sum of the series = 0.616667
Program in Java
The sum of the series = 0.616667
Program in Java
Here is the source code of the Java Program to find the sum of series 1/2-2/3+3/4-4/5+5/6 ...+N/N+1.
Code:
import java.util.Scanner;
public class p21 {
public static void main(String[] args) {
Scanner cs=new Scanner(System.in);
int n;
double sum=0.0,i;
System.out.println("Enter the range of number:");
n=cs.nextInt();
for(i=1;i<=n;i++)
{
if((int)i%2==0)
sum-=i/(i+1);
else
sum+=i/(i+1);
}
System.out.println("The sum of the series = "+sum);
cs.close();
}
}
public class p21 {
public static void main(String[] args) {
Scanner cs=new Scanner(System.in);
int n;
double sum=0.0,i;
System.out.println("Enter the range of number:");
n=cs.nextInt();
for(i=1;i<=n;i++)
{
if((int)i%2==0)
sum-=i/(i+1);
else
sum+=i/(i+1);
}
System.out.println("The sum of the series = "+sum);
cs.close();
}
}
Input/Output:
Enter the range of number:
9
The sum of the series = 0.6456349206349208
Program in Python
9
The sum of the series = 0.6456349206349208
Program in Python
Here is the source code of the Python Program to find the sum of series 1/2-2/3+3/4-4/5+5/6 ...+N/N+1.
Code:
print("Enter the range of number(Limit):")
n=int(input())
i=1
sum=0.0
while(i<=n):
if(i%2==0):
sum-=i/(i+1)
else:
sum+=i/(i+1)
i+=1
print("The sum of the series = ",sum)
n=int(input())
i=1
sum=0.0
while(i<=n):
if(i%2==0):
sum-=i/(i+1)
else:
sum+=i/(i+1)
i+=1
print("The sum of the series = ",sum)
Input/Output:
Enter the range of number(Limit):
21
The sum of the series = 0.6709359053399303
21
The sum of the series = 0.6709359053399303
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