Problem statement:- Program to Find the sum of series 1/2+2/3+3/4.....+(N-1)/N.
Data requirement:-
Input Data:- n
Output Data:-Sum
Additional Data:- i
Program in C
Input Data:- n
Output Data:-Sum
Additional Data:- i
Program in C
Here is the source code of the C Program to Find the sum of series 1/2+2/3+3/4.....+(N-1)/N.
Code:
#include<stdio.h>
int main()
{
int n;
double sum=0.0,i;
printf("Enter the range of number:");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
sum+=i/(i+1);
}
printf("The sum of the series = %0.2lf",sum);
}
Enter the range of number:5
The sum of the series = 3.55
Program in C++
Here is the source code of the C++ Program to Find the sum of series 1/2+2/3+3/4.....+(N-1)/N.
Code:
#include<iostream>
using namespace std;
int main()
{
int n;
double sum=0.0,i;
cout<<"Enter the range of number:";
cin>>n;
for(i=1;i<=n;i++)
{
sum+=i/(i+1);
}
cout<<"The sum of the series = "<<sum;
}
Enter the range of number:6
The sum of the series = 4.40714
Program in Java
Here is the source code of the Java Program to Find the sum of series 1/2+2/3+3/4.....+(N-1)/N.
Code:
import java.util.Scanner;
public class Sum_Of_Series4 {
public static void main(String[] args) {
Scanner cs=new Scanner(System.in);
int n;
double sum=0.0,i;
System.out.println("Enter the range of number:");
n=cs.nextInt();
for(i=1;i<=n;i++)
{
sum+=i/(i+1);
}
System.out.println("The sum of the series = "+sum);
cs.close();
}
}
Enter the range of number:
10
The sum of the series = 7.980122655122655
Program in Python
Here is the source code of the Python Program to Find the sum of series 1/2+2/3+3/4.....+(N-1)/N.
Code:
n=int(input("Enter the range of number:"))
sum=0.0
for i in range(1,n+1):
sum += i / (i + 1)
print("The sum of the series = ",sum)
Enter the range of number:4
The sum of the series = 2.716666666666667
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