Program to Find the sum of series 1/2+2/3+3/4.....+(N-1)/N

 Problem statement:- Program to Find the sum of series 1/2+2/3+3/4.....+(N-1)/N.

 Data requirement:-

   Input Data:- n

  Output Data:-Sum

  Additional Data:- i

Program in C
  
Here is the source code of the C Program to Find the sum of series 1/2+2/3+3/4.....+(N-1)/N.

Code:

#include<stdio.h>
int main()
{
    int n;
    double sum=0.0,i;
    printf("Enter the range of number:");
    scanf("%d",&n);

    for(i=1;i<=n;i++)
    {
            sum+=i/(i+1);
    }

    printf("The sum of the series = %0.2lf",sum);
}

Input/Output:
Enter the range of number:5
The sum of the series = 3.55

Program in C++

Here is the source code of the C++ Program to Find the sum of series 1/2+2/3+3/4.....+(N-1)/N.

Code:

#include<iostream>
using namespace std;
int main()
{
    int n;
    double sum=0.0,i;
    cout<<"Enter the range of number:";
    cin>>n;

    for(i=1;i<=n;i++)
    {
            sum+=i/(i+1);
    }
    cout<<"The sum of the series = "<<sum;
}

Input/Output:
Enter the range of number:6
The sum of the series = 4.40714

Program in Java

Here is the source code of the Java Program to Find the sum of series 1/2+2/3+3/4.....+(N-1)/N.

Code:

import java.util.Scanner;
public class Sum_Of_Series4 {

public static void main(String[] args) {
Scanner cs=new Scanner(System.in);
int n;
double sum=0.0,i;
     System.out.println("Enter the range of number:");
     n=cs.nextInt();
     for(i=1;i<=n;i++)
     {
             sum+=i/(i+1);
     }
     System.out.println("The sum of the series = "+sum);
     cs.close();
}
}

Input/Output:
Enter the range of number:
10
The sum of the series = 7.980122655122655

Program in Python

Here is the source code of the Python Program to Find the sum of series 1/2+2/3+3/4.....+(N-1)/N.

Code:

n=int(input("Enter the range of number:"))
sum=0.0
for i in range(1,n+1):
    sum += i / (i + 1)
print("The sum of the series = ",sum)

Input/Output:
Enter the range of number:4
The sum of the series =  2.716666666666667


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