Program to Find the sum of series 1+11+111.....+N

 Problem statement:- Program to Find the sum of series 1+11+111+1111.....+N.

 Data requirement:-

   Input Data:- n

  Output Data:-Sum

  Additional Data:- i, p

Program in C
  

Here is the source code of the C Program to Find the sum of series 1+11+111+1111.....+N.

Code:

#include<stdio.h>

int main()

{

    int n;

    int sum=0,i;

    printf("Enter the range of number:");

    scanf("%d",&n);

    int p=1;

    for(i=1;i<=n;i++)

    {

            sum+=p;

            p=(p*10)+1;

    }

    printf("The sum of the series = %d",sum);

}

Input/Output:

Enter the range of number:3

The sum of the series = 123

Program in C++

Here is the source code of the C++ Program to Find the sum of series 1+11+111+1111.....+N.

Code:

#include<iostream>

using namespace std;

int main()

{

    int n;

    int sum=0,i;

    cout<<"Enter the range of number:";

    cin>>n;

    int p=1;

    for(i=1;i<=n;i++)

    {

            sum+=p;

            p=(p*10)+1;

    }

    cout<<"The sum of the series = "<<sum;

}

Input/Output:

Enter the range of number:6

The sum of the series = 123456

Program in Java

Here is the source code of the Java Program to Find the sum of series 1+11+111+1111.....+N.

Code:

import java.util.Scanner;

public class Sum_Of_Series3 {

public static void main(String[] args) {

Scanner cs=new Scanner(System.in);

int n;

int sum=0,i;

     System.out.println("Enter the range of number:");

     n=cs.nextInt();

     int p=1;

     for(i=1;i<=n;i++)

     {

             sum+=p;

             p=(p*10)+1;

     }

     System.out.println("The sum of the series = "+sum);

     cs.close();

}

}

Input/Output:

Enter the range of number:

5

The sum of the series = 12345

Program in Python

Here is the source code of the Python Program to Find the sum of series 1+11+111+1111.....+N.

Code:

n=int(input("Enter the range of number:"))

sum=0

p=1

for i in range(1,n+1):

    sum += p

    p = (p * 10) + 1

print("The sum of the series = ",sum)

Input/Output:

Enter the range of number:9

The sum of the series =  123456789

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