Find sum of series 1/2!+2/3!+3/5!+.....N/(N+1)!

Problem Statement:- Program to find the sum of series 1/2!+2/3!+3/5!+4/6!+.....N/(N+1)!.

 Data requirement:-

   Input Data:- n

  Output Data:-Sum

  Additional Data :-i,fact,fa,num

Program in C
  

Here is the source code of the C Program to find the sum of series 1/2!+2/3!+3/5!+ 4/6!+.....N/(N+1)!.

Code:

#include <stdio.h>
/* this Function is Calculating Factorial of the Number */
int fact(int num)
{
  int i, fa = 1;
  for (i = 1; i <= num; i++)
  {
    fa *= i;
  }
  return fa;
}
int main()
{
  int n;
  double sum = 0.0, i;
  printf("Enter the range of number:");
  scanf("%d", &n);
  for (i = 1; i <= n; i++)
  {
    sum += i / fact(i + 1);
  }
  printf("The sum of the series = %0.2lf", sum);
}

Input/Output:

Enter the range of number:3
The sum of the series = 0.96

Program in C++
  

Here is the source code of the C++ Program to find the sum of series 1/2!+2/3!+3/5!+ 4/6!+.....N/(N+1)!.

Code:

#include <iostream>
using namespace std;
/* this Function is Calculating Factorial of the Number */
int fact(int num)
{
    int i, fa = 1;
    for (i = 1; i <= num; i++)
    {
        fa *= i;
    }
    return fa;
}
int main()
{
    int n;
    double sum = 0.0, i;
    cout << "Enter the range of number:";
    cin >> n;
    for (i = 1; i <= n; i++)
    {
        sum += i / fact(i + 1);
    }
    cout << "The sum of the series = " << sum;
}

Input/Output:

Enter the range of number:8
The sum of the series = 0.999997

Program in Java
  

Here is the source code of the C Program to find the sum of series 1/2!+2/3!+3/5!+ 4/6!+.....N/(N+1)!.

Code:

import java.util.Scanner;
/* this Function is Calculating Factorial of the Number */
public class SumOfSeries {
    static int fact(int num) {
        int i, fa = 1;
        for (i = 1; i <= num; i++) {
            fa *= i;
        }
        return fa;
    }
    public static void main(String[] args) {
        Scanner cs = new Scanner(System.in);
        int n, i;
        double sum = 0.0;
        System.out.println("Enter the range of number:");
        n = cs.nextInt();
        for (i = 1; i <= n; i++) {
            sum += (double) i / fact(i + 1);
        }
        System.out.println("The sum of the series = " + sum);
        cs.close();
    }
}

Input/Output:

Enter the range of number:
12
The sum of the series = 1.0000000041233323

Program in Python
  

Here is the source code of the Python Program to find the sum of series 1/2!+2/3!+3/5!+ 4/6!+.....N/(N+1)!.

Code:

def fact(num):
    i = 1
    fa = 1
    while(i <= num):
        fa *= i
        i += 1
    return fa
n = int(input("Enter the range of number(Limit):"))
i = 1
sum = 0.0
while(i <= n):
    sum += float(i/fact(i+1))
    i += 1
print("The sum of the series = ", sum)

Input/Output:

Enter the range of number(Limit):
3
The sum of the series =  0.9583333333333333

Most Recommend Questions:-

• Write a Program to find the sum of series 1!+2!+3!...+n!.
  

•  Write a program to find the sum of series 1!/1+2!/2+3!/3...+n!/n.
• 
  

• Write a program to find the sum of series 1/2!+2/3!+3/5!+4/6!+.....N/(N+1)!.

• Write a Program to find the sum of series 1^2+2^2+3^2...+N^2.

• Write a Program to Find the sum of series 1/1!+1/2!+1/3!+1/4!.....+1/N!.

More Questions:-

• Series Programming Questions and Solutions

• C/C++/Java/Python Practice Question