Check Armstrong number using recursion

SOURAV KUMAR PATRA December 05, 2020

Definition Of Armstrong Number:- Armstrong Number is a number that is equal to the sum of cubs its digits. 

Example:- 153=1^3 +5^3+3^3=1+125+27=153

                   407=4^3+0^3+7^3=64+0+343=407

Problem statement:- Program to check Armstrong number or not using recursion.

Data requirement:-

   Input Data:- num

  Output Data:-String Output

Program in C

Here is the source code of the C Program to check Armstrong number or not using recursion.

Code:

#include<stdio.h>
#include<math.h>
int check_ArmstrongNumber(int num)
{
     if(num>0)
    return (pow(num%10,3) +check_ArmstrongNumber(num/10));
}
int main()
{
    int num;
    printf("Enter a number:");
    scanf("%d",&num);
   if(check_ArmstrongNumber(num)==num)
    printf("It is an Armstrong Number");
   else
    printf("It is not an Armstrong Number");
}

Input/Output:
Enter a number:153
It is an Armstrong Number

Program in C++

Here is the source code of the C++ Program to check Armstrong number or not using recursion.

Code:

#include<iostream>
#include<cmath>
using namespace std;
int check_ArmstrongNumber(int num)
{
     if(num>0)
    return (pow(num%10,3) +check_ArmstrongNumber(num/10));
}
int main()
{
    int num;
    cout<<"Enter a number:";
    cin>>num;
   if(check_ArmstrongNumber(num)==num)
    cout<<"It is an Armstrong Number";
   else
    cout<<"It is not an Armstrong Number";
}

Input/Output:
Enter a number:225
It is not an Armstrong Number

Program in Java

Here is the source code of the Java Program to check Armstrong number or not using recursion.

Code:

import java.util.Scanner;
public class ArmstrongNumber {
int sum=0;
int check_ArmstrongNumber(int num)
{
if(num!=0)
{
sum+=Math.pow(num%10,3);
check_ArmstrongNumber(num/10);
}
return sum;
}
public static void main(String[] args) {
Scanner cs=new Scanner(System.in);
    int num;
    System.out.print("Enter a number:");
    num=cs.nextInt();
    ArmstrongNumber ob=new ArmstrongNumber();
    if(ob.check_ArmstrongNumber(num)==num)
    System.out.print("It is an Armstrong Number.");
       else
       System.out.print("It is not an Armstrong Number.");
    cs.close();
}
}

Input/Output:
Enter a number:370
It is an Armstrong Number.

Program in Python

Here is the source code of the Python Program to check Armstrong number or not using recursion.

Code:

sum=0
def check_ArmstrongNumber(num):
    global sum
    if (num!=0):
        sum+=pow(num%10,3)
        check_ArmstrongNumber(num//10)
    return sum
num=int(input("Enter a number:"))
if (check_ArmstrongNumber(num) == num):
    print("It is an Armstrong Number.")
else:
    print("It is not an Armstrong Number.")

Input/Output:
Tags:

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