Program to print Square Number series 1 4 9 16...N

Problem statement:- Program to Print Square Number series 1 4 9 16...N.


Data requirement:-

   Input Data:- n

  Output Data:-i


Program in C
  

Here is the source code of the C Program to Print Square Number series 1 4 9 16...N.


Code:

#include <stdio.h>
int main()
{
    int ni = 1;
    printf("Enter the range of number(Limit):");
    scanf("%d", &n);
    while (i <= n)
    {
        printf("%d "i * i);
        i++;
    }
}

Input/Output:
Enter the range of number(Limit):4
1 4 9 16

Program in C++
  

Here is the source code of the C++ Program to Print Square Number series 1 4 9 16...N.


Code:

#include <iostream>
using namespace std;
int main()
{
    int ni = 1;
    cout << "Enter the range of number(Limit):";
    cin >> n;

    while (i <= n)
    {
        cout << i * i << " ";
        i++;
    }
}

Input/Output:
Enter the range of number(Limit):6
1 4 9 16 25 36

Program in Java
  

Here is the source code of the Java Program to Print Square Number series 1 4 9 16...N.


Code:

import java.util.Scanner;

public class p8 {
    public static void main(String[] args) {
        Scanner cs = new Scanner(System.in);
        int ni = 1;
        System.out.println("Enter the range of number(Limit):");
        n = cs.nextInt();

        while (i <= n) {
            System.out.print(i * i + " ");
            i++;
        }
        cs.close();
    }
}

Input/Output:
Enter the range of number(Limit):
10
1 4 9 16 25 36 49 64 81 100 

Program in Python
  

Here is the source code of the Python Program to Print Square Number series 1 4 9 16...N.


Code:

n = int(input("Enter the range of number(Limit):"))
i = 1
while(i <= n):
    print(i*iend=" ")
    i += 1

Input/Output:
Enter the range of number(Limit):
3
1 4 9 


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