Problem statement:- Program to Print Square Number series 1 4 9 16...N.
Data requirement:-
Input Data:- n
Output Data:-i
Program in C
Here is the source code of the C Program to Print Square Number series 1 4 9 16...N.
Code:
#include <stdio.h>int main(){ int n, i = 1; printf("Enter the range of number(Limit):"); scanf("%d", &n); while (i <= n) { printf("%d ", i * i); i++; }}
Input/Output:
Enter the range of number(Limit):4
1 4 9 16
1 4 9 16
Program in C++
Here is the source code of the C++ Program to Print Square Number series 1 4 9 16...N.
Code:
#include <iostream>using namespace std;int main(){ int n, i = 1; cout << "Enter the range of number(Limit):"; cin >> n;
while (i <= n) { cout << i * i << " "; i++; }}
Input/Output:
Enter the range of number(Limit):6
1 4 9 16 25 36
1 4 9 16 25 36
Program in Java
Here is the source code of the Java Program to Print Square Number series 1 4 9 16...N.
Code:
import java.util.Scanner;
public class p8 { public static void main(String[] args) { Scanner cs = new Scanner(System.in); int n, i = 1; System.out.println("Enter the range of number(Limit):"); n = cs.nextInt();
while (i <= n) { System.out.print(i * i + " "); i++; } cs.close(); }}
Input/Output:
Enter the range of number(Limit):
10
1 4 9 16 25 36 49 64 81 100
10
1 4 9 16 25 36 49 64 81 100
Program in Python
Here is the source code of the Python Program to Print Square Number series 1 4 9 16...N.
Code:
n = int(input("Enter the range of number(Limit):"))i = 1while(i <= n): print(i*i, end=" ") i += 1
Input/Output:
Enter the range of number(Limit):
3
1 4 9
3
1 4 9
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