# Program to find the sum of series 1+3+5+7..+N

Problem statement:- Program to find the sum of series 1+3+5+7..+N

Data requirement:-

Input Data:- n

Output Data:- sum

Program in C

Here is the source code of the C Program to find the sum of series 1+3+5+7..+N.

Code:

#include<stdio.h>
int main()
{
int n,sum=0,i=1;
printf("Enter the range of number:");
scanf("%d",&n);

while(i<=n)

{
sum+=i;
i+=2;
}
printf("The sum of the series = %d",sum);
}

Input/Output:
Enter the range of number:9
The sum of the series = 25

Program in C++

Here is the source code of the C++ Program to find the sum of series 1+3+5+7..+N.

Code:

#include<iostream>
using namespace std;
int main()
{
int n,sum=0,i=1;
cout<<"Enter the range of number:";
cin>>n;

while(i<=n)

{
sum+=i;
i+=2;
}
cout<<"The sum of the series = "<<sum;
}

Input/Output:
Enter the range of number:13
The sum of the series = 49

Program in Java

Here is the source code of the Java Program to find the sum of series 1+3+5+7..+N.

Code:

import java.util.Scanner;
public class p2 {

public static void main(String[] args) {

Scanner cs=new Scanner(System.in);
int n,sum=0,i=1;
System.out.println("Enter the range of number:");
n=cs.nextInt();
while(i<=n)
{
sum+=i;
i+=2;
}
System.out.println("The sum of the series = "+sum);
cs.close();
}
}

Input/Output:
Enter the range of number:
27
The sum of the series = 196

Program in Python

Here is the source code of the Python Program to find the sum of series 1+3+5+7..+N.

Code:

print("Enter the range of number:")

n=int(input())
sum=0
i=1
while(i<=n):
sum+=i
i+=2
print("The sum of the series = ",sum)

Input/Output:
Enter the range of number:
51
The sum of the series =  676