Program to find the sum of series 1^2+2^2+3^2...+N^2

Problem statement:- Program to find the sum of series 1^2+2^2+3^2...+N^2

 Data requirement:-

   Input Data:- n

  Output Data:- sum

  Additional Data:- i

Program in C

  

Here is the source code of the C Program to find the sum of series 1^2+2^2+3^2...+N^2.

Code:

  

#include<stdio.h>
#include<math.h>
int main()
{
    int n,sum=0,i;
    printf("Enter the range of number:");
    scanf("%d",&n);
    for(i=1;i<=n;i++)
        sum+=i*i;
    printf("The sum of the series = %d",sum);
}

Input/Output:

Enter the range of number:11
The sum of the series = 506

Program in C++

  

Here is the source code of the C++ Program to find the sum of series 1^2+2^2+3^2...+N^2.

Code:

  

#include<iostream>
using namespace std;
int main()
{
    int n,sum=0,i;
    cout<<"Enter the range of number:";
    cin>>n;

    for(i=1;i<=n;i++)
        sum+=i*i;
    cout<<"The sum of the series = "<<sum;
}

Input/Output:

Enter the range of number:7
The sum of the series = 140

Program in Java

  

Here is the source code of the Java Program to find the sum of series 1^2+2^2+3^2...+N^2.

Code:

import java.util.Scanner;
public class p3 {

public static void main(String[] args) {
Scanner cs=new Scanner(System.in);
    int n,sum=0,i;
    System.out.println("Enter the range of number:");
    n=cs.nextInt();
    for(i=1;i<=n;i++)
        sum+=i*i;
    System.out.println("The sum of the series = "+sum);
    cs.close();
}
}

Input/Output:

Enter the range of number:
25
The sum of the series = 5525

Program in Python

  

Here is the source code of the Python Program to find the sum of series 1^2+2^2+3^2...+N^2.

Code:

print("Enter the range of number:")

n=int(input())
sum=0
for i in range(1,n+1):
    sum+=i*i
print("The sum of the series = ",sum)

Input/Output:

Enter the range of number:
31
The sum of the series =  10416

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