Problem statement:- Program to find the sum of series 1+2+3..+N
Data requirement:-
Input Data:- n
Output Data:- sum
Additional Data:- i
Program in C
Here is the source code of the C Program to find the sum of series 1+2+3..+N.
Code:
#include<stdio.h>
int main()
{
int n,sum=0,i;
printf("Enter the range of number:");
scanf("%d",&n);
for(i=1;i<=n;i++)
sum+=i;
printf("The sum of the series = %d",sum);
}
Input/Output:
Enter the range of number:8
The sum of the series = 36
Program in C++
Here is the source code of the C++ Program to find the sum of series 1+2+3..+N.
Code:
#include<iostream>
using namespace std;
int main()
{
int n,sum=0,i;
cout<<"Enter the range of number:";
cin>>n;
for(i=1;i<=n;i++)
sum+=i;
cout<<"The sum of the series = "<<sum;
}
Input/Output:
Enter the range of number:10
The sum of the series = 55
Program in Java
Here is the source code of the Java Program to find the sum of series 1+2+3..+N.
Code:
import java.util.Scanner;
public class p1 {
public static void main(String[] args) {
Scanner cs=new Scanner(System.in);
int n,sum=0,i;
System.out.println("Enter the range of number:");
n=cs.nextInt();
for(i=1;i<=n;i++)
sum+=i;
System.out.println("The sum of the series = "+sum);
cs.close();
}
}
Input/Output:
Enter the range of number:
17
The sum of the series = 153
Program in Python
Here is the source code of the Python Program to find the sum of series 1+2+3..+N.
Code:
print("Enter the range of number:")
n=int(input())
sum=0
for i in range(1,n+1):
sum+=i
print("The sum of the series = ",sum)
Input/Output:
Enter the range of number:
5
The sum of the series = 15
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