Program to find the sum of series 1+2+3..+N

Problem statement:- Program to find the sum of series 1+2+3..+N

 Data requirement:-

   Input Data:- n

  Output Data:- sum

  Additional Data:- i

Program in C

  

Here is the source code of the C Program to find the sum of series 1+2+3..+N.

Code:

  

#include<stdio.h>

int main()

{

    int n,sum=0,i;

    printf("Enter the range of number:");

    scanf("%d",&n);

    for(i=1;i<=n;i++)

        sum+=i;

    printf("The sum of the series = %d",sum);

}

Input/Output:

Enter the range of number:8

The sum of the series = 36

Program in C++

  

Here is the source code of the C++ Program to find the sum of series 1+2+3..+N.

Code:

  

#include<iostream>

using namespace std;

int main()

{

    int n,sum=0,i;

    cout<<"Enter the range of number:";

    cin>>n;

    for(i=1;i<=n;i++)

        sum+=i;

    cout<<"The sum of the series = "<<sum;

}

Input/Output:

Enter the range of number:10

The sum of the series = 55

Program in Java

  

Here is the source code of the Java Program to find the sum of series 1+2+3..+N.

Code:

import java.util.Scanner;

public class p1 {

public static void main(String[] args) {

    Scanner cs=new Scanner(System.in);

    int n,sum=0,i;

    System.out.println("Enter the range of number:");

    n=cs.nextInt();

    for(i=1;i<=n;i++)

        sum+=i;

    System.out.println("The sum of the series = "+sum);

    cs.close();

}

}

Input/Output:

Enter the range of number:

17

The sum of the series = 153

Program in Python

  

Here is the source code of the Python Program to find the sum of series 1+2+3..+N.

Code:

print("Enter the range of number:")

n=int(input())
sum=0
for i in range(1,n+1):
    sum+=i
print("The sum of the series = ",sum) 

Input/Output:

Enter the range of number:

5

The sum of the series =  15