Problem statement:- Program to Find the sum of series 1/1!+1/2!+1/3!+1/4!.....+1/N!.
Data requirement:-
Input Data:- n
Output Data:-Sum
Additional Data:- i, fact
Program in C
Input Data:- n
Output Data:-Sum
Additional Data:- i, fact
Program in C
Here is the source code of the C Program to Find the sum of series 1/1!+1/2!+1/3!+1/4!.....+1/N!.
Code:
#include<stdio.h>
int main()
{
int n,i,fact=1;
double sum=0.0;
printf("Enter the range of number:");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
fact*=i;
sum+=1.0/(double)fact;
}
printf("The sum of the series = %0.2lf",sum);
}
Enter the range of number:5
The sum of the series = 1.72
Program in C++
Here is the source code of the C++ Program to Find the sum of series 1/1!+1/2!+1/3!+1/4!.....+1/N!.
Code:
#include<iostream>
using namespace std;
int main()
{
int n,i,fact=1;
double sum=0.0;
cout<<"Enter the range of number:";
cin>>n;
for(i=1;i<=n;i++)
{
fact*=i;
sum+=1.0/(double)fact;
}
cout<<"The sum of the series = "<<sum;
}
Enter the range of number:8
The sum of the series = 1.71828
Program in Java
Here is the source code of the Java Program to Find the sum of series 1/1!+1/2!+1/3!+1/4!.....+1/N!.
Code:
import java.util.Scanner;
public class Sum_Of_Series7 {
public static void main(String[] args) {
Scanner cs=new Scanner(System.in);
int n,i,fact=1;
double sum=0.0;
System.out.println("Enter the range of number:");
n=cs.nextInt();
for(i=1;i<=n;i++)
{
fact*=i;
sum+=1.0/(double)fact;
}
System.out.println("The sum of the series = "+sum);
cs.close();
}
}
Enter the range of number:
10
The sum of the series = 1.7182818011463847
Program in Python
Here is the source code of the Python Program to Find the sum of series 1/1!+1/2!+1/3!+1/4!.....+1/N!.
Code:
n=int(input("Enter the range of number:"))
sum=0.0
fact=1
for i in range(1,n+1):
fact *= i
sum+=1.0/fact
print("The sum of the series = ",sum)
Enter the range of number:15
The sum of the series = 1.7182818284589947
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