Problem statement:- Program to Find the sum of N numbers in an array.
Data requirement:-
Input Data:- arr,size
Output Data:-size,arr
Output Data:-size,arr
Additional Data:- i, j
Program in C
Here is the source code of the C Program to Find the sum of N numbers in an array.
Code:
#include<stdio.h>
int main()
{
printf("Enter the size of the array:");
int size;
scanf("%d",&size);
double arr[size],sum=0.0;
int i=0,j=0;
printf("Enter the Element of the array:\n");
while(i<size)
{
scanf("%lf",&arr[i]);
i++;
}
while(j<size)
{
sum+=arr[j];
j++;
}
printf("sum of %d number : %0.2lf",size,sum);
}
int main()
{
printf("Enter the size of the array:");
int size;
scanf("%d",&size);
double arr[size],sum=0.0;
int i=0,j=0;
printf("Enter the Element of the array:\n");
while(i<size)
{
scanf("%lf",&arr[i]);
i++;
}
while(j<size)
{
sum+=arr[j];
j++;
}
printf("sum of %d number : %0.2lf",size,sum);
}
Enter the size of the array:5
Enter the Element of the array:
10
35.4
47
85
98
sum of 5 number : 275.40
Enter the Element of the array:
10
35.4
47
85
98
sum of 5 number : 275.40
Program in C++
Here is the source code of the C++ Program to Find the sum of N numbers in an array.
Code:
#include<iostream>
using namespace std;
int main()
{
cout<<"Enter the size of the array:";
int size;
cin>>size;
double arr[size],sum=0.0;
int i=0,j=0;
cout<<"Enter the Element of the array:\n";
while(i<size)
{
cin>>arr[i];
i++;
}
while(j<size)
{
sum+=arr[j];
j++;
}
cout<<"sum of "<<size<<" number : "<<sum;
}
using namespace std;
int main()
{
cout<<"Enter the size of the array:";
int size;
cin>>size;
double arr[size],sum=0.0;
int i=0,j=0;
cout<<"Enter the Element of the array:\n";
while(i<size)
{
cin>>arr[i];
i++;
}
while(j<size)
{
sum+=arr[j];
j++;
}
cout<<"sum of "<<size<<" number : "<<sum;
}
Input/Output:
Enter the size of the array:4
Enter the Element of the array:
45
95
55.26
78.5
sum of 4 number : 273.76
Enter the Element of the array:
45
95
55.26
78.5
sum of 4 number : 273.76
Program in Java
Here is the source code of the Java Program to Find the sum of N numbers in an array.
Code:
import java.util.Scanner;
public class p6 {
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
System.out.println("Enter the size of the array:");
int size;
size=sc.nextInt();
double arr[ ]=new double[size];
double sum=0.0;
int i=0,j=0;
System.out.println("Enter the Element of the array:");
while(i<size)
{
arr[i]=sc.nextDouble();
i++;
}
while(j<size)
{
sum+=arr[j];
j++;
}
System.out.println("sum of "+size+" number : "+sum);
sc.close();
}
}
public class p6 {
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
System.out.println("Enter the size of the array:");
int size;
size=sc.nextInt();
double arr[ ]=new double[size];
double sum=0.0;
int i=0,j=0;
System.out.println("Enter the Element of the array:");
while(i<size)
{
arr[i]=sc.nextDouble();
i++;
}
while(j<size)
{
sum+=arr[j];
j++;
}
System.out.println("sum of "+size+" number : "+sum);
sc.close();
}
}
Enter the size of the array:
7
Enter the Element of the array:
48
65
32.56
89.22
45
65
78
sum of 7 number : 422.78
7
Enter the Element of the array:
48
65
32.56
89.22
45
65
78
sum of 7 number : 422.78
Program in Python
Here is the source code of the Python Program to Find the sum of N numbers in an array.
Code:
arr=[]
size = int(input("Enter the size of the array: "))
print("Enter the Element of the array:")
for i in range(0,size):
num = float(input())
arr.append(num)
sum=0.0
for j in range(0,size):
sum+= arr[j]
print("sum of ",size," number : ",sum)
size = int(input("Enter the size of the array: "))
print("Enter the Element of the array:")
for i in range(0,size):
num = float(input())
arr.append(num)
sum=0.0
for j in range(0,size):
sum+= arr[j]
print("sum of ",size," number : ",sum)
Enter the size of the array: 3
Enter the Element of the array:
25.5
100.6
95.3
sum of 3 number : 221.39999999999998
Enter the Element of the array:
25.5
100.6
95.3
sum of 3 number : 221.39999999999998
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