Program to Find nth Perfect Square Number

Perfect Square Number means the product of two same natural numbers.

Example:
               5*5=10
               6*6=36
               2*2=4
                             
Problem statement:-  Program to Find nth Perfect Square Number.

Data requirement:-

   Input Data:- rangenumber

   Output Data:- rangenumber, letest

   Additional Data:- cnum, num1, sqr

Program in C

Here is the source code of the C Program to Find nth Perfect Square Number.

Code:

//nth perfect square Number
#include <stdio.h>
#include<math.h>
int
main ()
{
  int i, rangenumber, num = 1, c = 0, letest = 0, j;
  printf ("Enter the Nth value:");
  scanf ("%d", &rangenumber);

  while (c != rangenumber)
    {
      int num1=num;
      double sqr=sqrt(num1);
     if(sqr-floor(sqr)==0)
      {
          c++;
          letest=num;
      }
      num = num + 1;
    }
  printf ("%dth Perfect Square number is %d", rangenumber, letest);
  return 0;
}

Input/Output:
Enter the Nth value:4
4th Perfect Square number is 16

Program in C++

Here is the source code of the C++ Program to Find nth Perfect Square Number.

Code:

//nth perfect square Number
#include <iostream>
#include<cmath>
using namespace std;
int
main ()
{
  int i, rangenumber, num = 1, c = 0, letest = 0;
  cout<<"Enter the Nth value:";
  cin>>rangenumber;

  while (c != rangenumber)
    {
      int num1=num;
      double sqr=sqrt(num1);
     if(sqr-floor(sqr)==0)
      {
          c++;
          letest=num;
      }
      num = num + 1;
    }
  cout<<rangenumber<<"th Perfect Square number is "<<letest;
  return 0;
}

Input/Output:
Enter the Nth value:7
7th Perfect Square number is 49

Program in Java
  
Here is the source code of the Java Program to Find nth Perfect Square Number.

Code:

import java.util.Scanner;
public class NthPerfectSquareNumber {

public static void main(String[] args) {
Scanner cs=new Scanner(System.in);
int  rangenumber, num = 1, c = 0, letest = 0;
  System.out.println("Enter Nth number:");
  rangenumber=cs.nextInt();

  while (c != rangenumber)
    {
      int num1=num;
      double sqr=Math.sqrt(num1);
     if(sqr-Math.floor(sqr)==0)
      {
          c++;
          letest=num;
      }
      num = num + 1;
    }
System.out.println(rangenumber+"th Perfect Square number is "+letest);
cs.close();
}
}

Input/Output:
Enter Nth number:
10
10th Perfect Square number is 100

Program in Python
  
Here is the source code of the Python Program to Find nth Perfect Square Number.

Code:

import math
rangenumber=int(input("Enter a Nth Number:"))
c = 0
letest = 0
num = 1
while c != rangenumber:
    num1 = num
    sqr = math.sqrt(num1)
    if sqr-math.floor(sqr)==0:
        c+=1
        letest = num

    num = num + 1
print(rangenumber,"th Perfect Square number is ",latest)

Input/Output:
Enter a Nth Number:14
14 th Perfect Square number is  196

More:-

C/C++/Java/Python Practice Question 

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