Check whether number is Disarium Number or Not

SOURAV KUMAR PATRA August 03, 2020
A Number is a Disarium number if the sum of the digits powered with their respective positions is equal to the number itself.

Example:

               Given Number=135
               135⇒1¹+3²+5³=1+9+125=135
               so, 135 is Disarium Number.
                 
                Given Number=120
               120⇒1¹+2²+0³=1+4+0=5
               so, 120 is not a Disarium Number.
                                          
Problem statement:-  Program to check whether the number is Disarium Number or Not.

Data requirement:-

   Input Data:- num

   Output Data:- String output

   Additional Data:- num1, c, sum, rem
Program in C

Here is the source code of the C Program to check whether the number is Disarium Number or Not.

Code:

///Disarium Number Or Not
#include<stdio.h>
#include<math.h>
int main()
{
    int num;
    printf("Enter the number:");
    scanf("%d",&num);
    int num1=num,c=0;
    while(num1!=0)
    {
        num1/=10;
        c++;
    }
    num1=num;
    int sum=0;
    while(num1!=0)
    {
        int rem=num1%10;
        sum+=pow(rem,c);
        num1/=10;
        c--;
    }
   if(sum==num)
    printf("It is a Disarium Number.");
   else
    printf("It is not a Disarium Number.");
}

Input/Output:
Enter the number:135                                                                                                                
It is a Disarium Number.    

Program in C++

Here is the source code of the C++ Program to check whether the number is Disarium Number or Not.

Code:

#include <iostream>
#include<cmath>
using namespace std;
int main()
{
    int num,i;
    cout<<"Enter the number:";
    cin>>num;
    int num1=num,c=0;
    while(num1!=0)
    {
        num1/=10;
        c++;
    }
    num1=num;
    int sum=0;
    while(num1!=0)
    {
        int rem=num1%10;
        sum+=pow(rem,c);
        num1/=10;
        c--;
    }
   if(sum==num)
    cout<<"It is a Disarium Number.";
   else
    cout<<"It is not a Disarium Number.";
}

Input/Output:
Enter the number:120
It is not a Disarium Number.

Program in Java
  
Here is the source code of the Java Program to check whether the number is Disarium Number or Not.

Code:

import java.util.Scanner;
public class DisariumNumberOrNot {

 public static void main(String[] args) {
Scanner cs=new Scanner(System.in);
     int num;
     System.out.println("Enter a number:");
     num=cs.nextInt();
     int num1=num,c=0;
     while(num1!=0)
     {
         num1/=10;
         c++;
     }
     num1=num;
     int sum=0;
     while(num1!=0)
     {
         int rem=num1%10;
         sum+=Math.pow(rem,c);
         num1/=10;
         c--;
     }
    if(sum==num)
      System.out.println("It is a Disarium Number.");
    else
         System.out.println("It is not a Disarium Number.");
  cs.close();

 }

 Input/Output:
Enter a number:
175
It is a Disarium Number.

Program in Python
  
Here is the source code of the Program to check whether the number is Disarium Number or Not.

Code:

import math
num=int(input("Enter a number:"))
num1 = num
c=0
while num1!=0:
    num1 //= 10
    c+=1
num1=num
sum=0
while num1!=0:
    rem = num1 % 10
    sum += math.pow(rem, c)
    num1 //= 10
    c-=1
if sum==num:
    print("It is a Disarium Number.")
else:
   print("It is Not a Disarium Number.")

 Input/Output:
Tags:

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