# Print perfect square numbers in a given range

### Example:-

4,9,16.....

#### Sample Input/Output:-

Sample Input First: 2 20                      Sample Output First: 4 9 16

Sample Input Second: 50 100             Sample Output Second64 81 100

#### Data requirement:-

Input Data:- fristnumber, endnumber

Output Data:-i

Program in C

Here is the source code of the C Program to Find out all perfect square numbers present within a given range.

Code:

#include <stdio.h>
#include<math.h>
int main()
{
int i, firstnum, endnumber;
printf ("Enter the first number:");
scanf ("%d", &firstnum);
printf ("Enter the second number:");
scanf ("%d", &endnumber);

printf ("perfect squares between %d and %d: \n", firstnum, endnumber);
for(i=firstnum;i<=endnumber;i++)
{
double sqr=sqrt(i);
if(sqr-floor(sqr)==0)
printf("%d ",i);
}
return 0;
}

Input/Output:
Enter the first number:
2
Enter the second number:20
perfect squares between 2 and 20:
4 9 16

Program in C++

Here is the source code of the C++ Program to print perfect square numbers in a given range.

Code:

#include<iostream>
#include<math.h>
using namespace std;
int main()
{
int range1,range2;
cout<<"Enter a range:";
cin>>range1>>range2;
int count=0;
cout<<"Perfect numbers between "<<range1<<" and "<<range2<<" are: ";
for(int i=range1;i<=range2;i++)
{
double sqr=sqrt(i);

if(sqr-floor(sqr)==0)
cout<<i<<" ";
}
}

Input/Output:
Enter a range:
50
100
Perfect numbers between 50 and 100 are: 64 81 100

Program in Java

Here is the source code of the Java Program to Find out all perfect square numbers present within a given range.

Code:

import java.util.Scanner;
public class PerfectSquareNumberInRange {

public static void main(String[] args) {
Scanner cs=new Scanner(System.in);
int firstnumber, endnumber, i;
System.out.println("Enter the First number:");
firstnumber=cs.nextInt();
System.out.println("Enter the Last number:");
endnumber=cs.nextInt();
System.out.println("Perfect squares numbers between "+fristnumber+" and "+endnumber+" are:");
for(i=firstnumber;i<=endnumber;i++)
{
double sqr=Math.sqrt(i);

if(sqr-Math.floor(sqr)==0)
System.out.print(i+" ");
}
cs.close();
}
}

Input/Output:
Enter the First number:
200
Enter the Last number:
300
Perfect squares numbers between 200 and 300 are:
225 256 289

Program in Python

Here is the source code of the Python Program to print perfect square numbers in a given range.

Code:

import math
print("Enter range:")
range1=int(input())
range2=int(input())
print("Perfect squares between ",range1," and ",range2," are: ")
for i in range(range1,range2+1):
sqr=math.sqrt(i)
if sqr-math.floor(sqr)==0:
print(i,end=" ")

Input/Output:
Enter range:
300
500
Perfect squares between  300  and  500  are:
324 361 400 441 484