Problem statement:- Program to print series 1,-2,6,-15,31...N.
Example:
Input: n=5
Output: 1 -2 6 -15 31 /* 1 (0+2)*-1 (2+2²) (6+3²)*-1 (15+4²)*/
Data requirement:-
Input Data:- n
Output Data:-pr
Additional Data:- i.
Program in C
Input Data:- n
Output Data:-pr
Additional Data:- i.
Program in C
Here is the source code of the C Program to print series 1,-2,6,-15,31...n.
Code:
#include<stdio.h>
#include<math.h>
int main()
{
int n,i,pr=1;
printf("Enter the range of number(Limit):");
scanf("%d",&n);
for(i=1;i<=n;i++)
{
if(i%2==0)
{
printf("%d ",-1*pr);
}
else
{
printf("%d ",pr);
}
pr=pr+pow(i,2);
}
}
Enter the range of number(Limit):5
1 -2 6 -15 31
Program in C++
Here is the source code of the C++ Program to print series 1,-2,6,-15,31...n.
Code:
#include<iostream>
#include<cmath>
using namespace std;
int main()
{
int n,i,pr=1;
cout<<"Enter the range of number(Limit):";
cin>>n;
for(i=1;i<=n;i++)
{
if(i%2==0)
{
cout<<-1*pr<<" ";
}
else
{
cout<<pr<<" ";
}
pr=pr+pow(i,2);
}
}
Enter the range of number(Limit):7
1 -2 6 -15 31 -56 92
Program in Java
Here is the source code of the Java Program to print series 1,-2,6,-15,31...n.
Code:
import java.util.Scanner;
public class Print_Series5 {
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
int n,i,pr=1;
System.out.printf("Enter the range of number(Limit):");
n=sc.nextInt();
for(i=1;i<=n;i++)
{
if(i%2==0)
{
System.out.print(-1*pr+" ");
}
else
{
System.out.print(pr+" ");
}
pr=(int) (pr+Math.pow(i,2));
}
sc.close();
}
}
Enter the range of number(Limit):6
1 -2 6 -15 31 -56
Program in Python
Here is the source code of the Python Program to print series 1,-2,6,-15,31...n.
Code:
n=int(input("Enter the range of number(Limit):"))
i=1
pr=1
while i<=n:
if(i%2==0):
print(-1*pr,end=" ")
else:
print(pr, end=" ")
pr+=pow(i,2)
i+=1
Enter the range of number(Limit):9
1 -2 6 -15 31 -56 92 -141 205
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