Program to print series 6,11,21,36,56...n

Problem statement:- Program to print series 6,11,21,36,56...n.

 Data requirement:-

   Input Data:- n

  Output Data:-pr

  Additional Data:- i, diff.

Program in C
  

Here is the source code of the C Program to print series 6,11,21,36,56...n.

Code:

#include<stdio.h>

int main()

{

    int n,i,pr=6,diff=5;

    printf("Enter the range of number(Limit):");

    scanf("%d",&n);

    for(i=1;i<=n;i++)

    {

        printf("%d ",pr);

        pr=pr+diff;

        diff=diff+5;

    }

}

Input/Output:

Enter the range of number(Limit):5

6 11 21 36 56

Program in C++

Here is the source code of the C++ Program to print series 6,11,21,36,56...n.

Code:

#include<iostream>

using namespace std;

int main()

{

    int n,i,pr=6,diff=5;

    cout<<"Enter the range of number(Limit):";

    cin>>n;

    for(i=1;i<=n;i++)

    {

        cout<<pr<<" ";

        pr=pr+diff;

        diff=diff+5;

    }

}

Input/Output:

Enter the range of number(Limit):7

6 11 21 36 56 81 111

Program in Java

Here is the source code of the Java Program to print series 6,11,21,36,56...n.

Code:

import java.util.Scanner;

public class Print_Series6 {

public static void main(String[] args) {

Scanner sc=new Scanner(System.in);

int n,i,pr=6,diff=5;

   System.out.printf("Enter the range of number(Limit):");

    n=sc.nextInt();

    for(i=1;i<=n;i++)

    {

    System.out.print(pr+" ");

    pr=pr+diff;

        diff=diff+5;

    }

    sc.close();

}

}

Input/Output:

Enter the range of number(Limit):8

6 11 21 36 56 81 111 146 

Program in Python

Here is the source code of the Python Program to print series 6,11,21,36,56...n.

Code:

n=int(input("Enter the range of number(Limit):"))

i=1

pr=6

diff=5

while i<=n:

    print(pr,end=" ")

    pr = pr + diff

    diff = diff + 5

    i+=1

Input/Output:

Enter the range of number(Limit):4

6 11 21 36 

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