Problem statement:- Program to find the sum of series (1+(1+2)+(1+2+3)+...till N)
Data requirement:-
Input Data:- n
Output Data:-Sum
Additional Data:-i, j
Program in C
Here is the source code of the C Program to find the sum of series (1+(1+2)+(1+2+3)+...till N).
Code:
#include<stdio.h>
int main()
{
int n,i=1,j,sum=0;
printf("Enter the range of number:");
scanf("%d",&n);
while(i<=n)
{
for(j=1;j<=i;j++){
sum+=j;
}
i++;
}
printf("The sum of the series = %d",sum);
}
int main()
{
int n,i=1,j,sum=0;
printf("Enter the range of number:");
scanf("%d",&n);
while(i<=n)
{
for(j=1;j<=i;j++){
sum+=j;
}
i++;
}
printf("The sum of the series = %d",sum);
}
Input/Output:
Enter the range of number:7
The sum of the series = 84
The sum of the series = 84
Program in C++
Here is the source code of the C++ Program to find the sum of series (1+(1+2)+(1+2+3)+ ...till N).
Code:
#include<iostream>
#include<cmath>
using namespace std;
int main()
{
int n,i=1,j,sum=0;
cout<<"Enter the range of number:";
cin>>n;
while(i<=n)
{
for(j=1;j<=i;j++){
sum+=j;
}
i++;
}
cout<<"The sum of the series = "<<sum;
}
#include<cmath>
using namespace std;
int main()
{
int n,i=1,j,sum=0;
cout<<"Enter the range of number:";
cin>>n;
while(i<=n)
{
for(j=1;j<=i;j++){
sum+=j;
}
i++;
}
cout<<"The sum of the series = "<<sum;
}
Input/Output:
Enter the range of number:11
The sum of the series = 286
The sum of the series = 286
Program in Java
Here is the source code of the Java Program to find the sum of series (1+(1+2)+(1+2+3)+ ...till N).
Code:
import java.util.Scanner;
public class p14 {
public static void main(String[] args) {
Scanner cs=new Scanner(System.in);
int n,i=1,j,sum=0;
System.out.println("Enter the range of number:");
n=cs.nextInt();
while(i<=n)
{
for(j=1;j<=i;j++){
sum+=j;
}
i++;
}
System.out.println("The sum of the series = "+sum);
cs.close();
}
}
public class p14 {
public static void main(String[] args) {
Scanner cs=new Scanner(System.in);
int n,i=1,j,sum=0;
System.out.println("Enter the range of number:");
n=cs.nextInt();
while(i<=n)
{
for(j=1;j<=i;j++){
sum+=j;
}
i++;
}
System.out.println("The sum of the series = "+sum);
cs.close();
}
}
Input/Output:
Enter the range of number:
20
The sum of the series = 1540
20
The sum of the series = 1540
Program in Python
Here is the source code of the Python Program to find the sum of series (1+(1+2)+(1+2+3)+ ...till N).
Code:
print("Enter the range of number:")
n=int(input())
print("Enter the value of x:")
x=int(input())
sum=0
i=1
while(i<=n):
for j in range(1,i+1):
sum+=j
i+=1
print("The sum of the series = ",sum)
n=int(input())
print("Enter the value of x:")
x=int(input())
sum=0
i=1
while(i<=n):
for j in range(1,i+1):
sum+=j
i+=1
print("The sum of the series = ",sum)
Enter the range of number:
33
The sum of the series = 6545
33
The sum of the series = 6545
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