Program to Find the nth Palindrome Number

SOURAV KUMAR PATRA July 31, 2020
Palindrome Number: remains the same when it's reverse the digits.

Example:
               212
               717
              
Problem statement:-  Program to Find the nth Palindrome Number.

Data requirement:-

   Input Data:- rangenumber

   Output Data:- rangenumber, letest

   Additional Data:- c, num, num1, sum, rem, num2

Program in C

Here is the source code of the C Program to Find the nth Palindrome Number.

Code:

//Write a program to find the nth palindrome number.
#include <stdio.h>
int
main ()
{
  int i, rangenumber, num = 1, c = 0, letest = 0;
  printf ("Enter the Nth value:");
  scanf ("%d", &rangenumber);

   while (c != rangenumber)
    {
      int num1=num;
      int num2=0;
    while(num1!=0)
    {
        int rem=num1%10;
        num1/=10;
        num2=num2*10+rem;
    }
    if(num==num2)
      {
          c++;
          letest=num;
      }
      num = num + 1;
    }
  printf ("%dth palindrome number is %d", rangenumber, letest);
  return 0;
}

Input/Output:
Enter the Nth value:15
15th palindrome number is 66

Program in C++

Here is the source code of the C++ Program to Find the nth Palindrome Number.

Code:

#include <iostream>
using namespace std;
int
main ()
{
  int i, rangenumber, num = 1, c = 0, letest = 0;
  cout<<"Enter the Nth value:";
  cin>>rangenumber;

   while (c != rangenumber)
    {
      int num1=num;
      int num2=0;
      //reverse of number
    while(num1!=0)
    {
        int rem=num1%10;
        num1/=10;
        num2=num2*10+rem;
    }
    if(num==num2)
      {
          c++;
          letest=num;
      }
      num = num + 1;
    }
  cout<<rangenumber<<"th palindrome number is "<<letest;
  return 0;
}

Input/Output:
Enter the Nth value:19
19th palindrome number is 101

Program in Java
  
Here is the source code of the Java Program to Find the nth Palindrome Number.

Code:

import java.util.Scanner;
public class NthPalindromeNumber {

 public static void main(String[] args) {
Scanner cs=new Scanner(System.in);
int  rangenumber, num = 1, c = 0, letest = 0;
  System.out.println("Enter Nth number:");
  rangenumber=cs.nextInt();

   while (c != rangenumber)
    {
  int num1=num;
      int num2=0;
    while(num1!=0)
    {
        int rem=num1%10;
        num1/=10;
        num2=num2*10+rem;
    }
    if(num==num2)
      {
          c++;
          letest=num;
      }
      num = num + 1;
    }
System.out.println(rangenumber+"th Palindrome Number is "+letest);
cs.close();
}
}

Input/Output:
Enter Nth number:
23
23th Palindrome Number is 141
Program in Python
  
Here is the source code of the Python Program to Find the nth Palindrome Number.

Code:

rangenumber=int(input("Enter a Nth Number:"))
c = 0
letest = 0
num = 1
while c != rangenumber:
    num2=0
    num1 = num
    while num1 != 0:
        rem = num1 % 10
        num1 //= 10
        num2 = num2 * 10 + rem
    if num==num2:
        c+=1
        letest = num

     num = num + 1
print(rangenumber,"th Palindrome Number is ",letest)

Input/Output:
Tags:

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1 Comments

  1. UnknownFebruary 2, 2021 at 7:47 PM

    No need for iteration here, this can be done by checking the structure of palindromic numbers. Can be solved in nearly linear time like this (JS solution):

    let findReverseNumber = n => {
    if ((n-=10)<10) return n>0 ? n*11 : n+9;
    let $ = new Leap(2);
    while (n >= $.skipped) n -= $.skipped, $ = new Leap($.digits + 1);
    if (n-- && !($.digits % 2)) return (1*10**($.digits/2-1)+n).getPalindrome();
    return (1*10**(($.digits-1)/2-1)+Math.floor(n/10)).getPalindrome(n%10);
    };

    Number.prototype.getPalindrome = function(_='', half=''+this, middle=''+_){
    return half + middle + [...half].reverse().join``;
    };

    class Leap {
    constructor(d){
    this.digits = d;
    this.skipped = 9*10**~~((d-1)/2);
    };
    };

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