Check a given number is an Armstrong Number

Armstrong Number:- A Number is an Armstrong Number if the sum of cubes of digits of the number is equal to Given Number.

Example:-

153, 307, 407....

Problem statement:- Program to check whether a given number is an Armstrong number or not.

Sample Input/Output:-

Sample Input First: 250                         Sample Output First: It is not an Armstrong Number

Sample Input Second: 153                    Sample Output Second: It is an Armstrong Number

Explanation:- 

For output 1st:  sum of cubes of digits(250)=2³+5³+0³=8+125+0=133 ≠ Given Number

For output 2nd: sum of cubes of digits(153)=1³+5³+3³=1+125+27=153  = Given Number

Data requirement:-

   Input Data:- num

  Output Data:-String Output

  Additional Data:- num2, sum, rem

Program in C
  

Here is the source code of the C Program to find the sum of first n natural numbers.

Code:

#include<stdio.h>

int main()

{

    int num;

    printf("Enter a number:");

    scanf("%d",&num);

    int num2=num;

    int sum=0;

   while(num!=0)

   {

       int rem=num%10;

       num=num/10;

       sum=sum+rem*rem*rem;

   }

   if(sum==num2)

    printf("It is an Armstrong Number");

   else

    printf("It is not an Armstrong Number");

}

Input/Output:

Enter a number:250

It is not an Armstrong Number

Program in C++
  

Here is the source code of the C++ Program to find the sum of first n natural numbers.

Code:

#include<iostream>

using namespace std;

int main()

{

    int num;

    cout<<"Enter a number:";

    cin>>num;

    int num2=num;

    int sum=0;

   while(num!=0)

   {

       int rem=num%10;

       num=num/10;

       sum=sum+rem*rem*rem;

   }

   if(sum==num2)

    cout<<"It is an Armstrong Number";

   else

    cout<<"It is not an Armstrong Number";

}

Input/Output:

Enter a number:153

It is an Armstrong Number

Program in Java
  

Here is the source code of the Java Program to find the sum of first n natural numbers.

Code:

import java.util.Scanner;

public class ArmstrongNumberNumberOrNot {

public static void main(String[] args) {

Scanner cs=new Scanner(System.in);

int num;

    System.out.println("Enter a number:");

    num=cs.nextInt();

    int num2=num;

    int sum=0;

   while(num!=0)

   {

       int rem=num%10;

       num=num/10;

       sum=sum+rem*rem*rem;

   }

   if(sum==num2)

    System.out.println("It is an Armstrong Number");

   else

    System.out.println("It is not an Armstrong Number");

cs.close();

}

}

Input/Output:

Enter a number:

407

It is an Armstrong Number

Program in Python
  

Here is the source code of the Python Program to find the sum of first n natural numbers.

Code:

'num=int(input("Enter a number:"))

num2=num
sum=0
while(num!=0):
   rem=num%10
   num=int(num/10)
   sum=sum+rem*rem*rem
if sum==num2:
   print("It is an Armstrong Number")
else:
   print("It is not an Armstrong Number")

Input/Output:

Enter a number:555

It is not an Armstrong Number

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