Check whether number is Neon Number or Not.

A Number is a Neon Number if the sum of digits of square of the number is equal to the number itself.

Example:

               Given Number=9
                square of 9=9*9=81
               sum of digits of square=8+1=9
                                          
Problem statement:-  Program to check whether the number is Neon Number or Not.

Data requirement:-

   Input Data:- num

   Output Data:- String output

   Additional Data:- num1, sum, rem, sqr

Program in C

Here is the source code of the C Program to check whether the number is Neon Number or Not.

Code:

//Neon Number Or Not
#include<stdio.h>
int main()
{
    int num,i;
    printf("Enter the number:");
    scanf("%d",&num);

    int sqr=num*num;
     //Sum of digit
    int sum=0,rem;
    while(sqr!=0)
    {
        rem=sqr%10;
        sum+=rem;
        sqr/=10;
    }

   if(sum==num)
    printf("It is a Neon Number.");
   else
    printf("It is not a Neon Number.");
}

Input/Output:

Enter the number:9
It is a Neon Number.

Program in C++

Here is the source code of the C++ Program to check whether the number is Neon Number or Not.

Code:

#include <iostream>
using namespace std;
int main()
{
    int num,i;
    cout<<"Enter the number:";
    cin>>num;

    int sqr=num*num;
     //Sum of digit
    int sum=0,rem;
    while(sqr!=0)
    {
        rem=sqr%10;
        sum+=rem;
        sqr/=10;
    }

   if(sum==num)
    cout<<"It is a Neon Number.";
   else
    cout<<"It is not a Neon Number.";
}

Input/Output:

Enter the number:1
It is a Neon Number.

Program in Java

  

Here is the source code of the Java Program to check whether the number is Neon Number or Not.

Code:

import java.util.Scanner;
public class NeonNumberOrNot {

public static void main(String[] args) {
Scanner cs=new Scanner(System.in);
     int num;
     System.out.println("Enter a number:");
     num=cs.nextInt();
     int sqr=num*num;
     //Sum of digit
    int sum=0,rem;
    while(sqr!=0)
    {
        rem=sqr%10;
        sum+=rem;
        sqr/=10;
    }

   if(sum==num)
      System.out.println("It is a Neon Number.");
    else
         System.out.println("It is not a Neon Number.");
  cs.close();
}
}

Input/Output:

Enter a number:
10
It is not a Neon Number.

Program in Python
  

Here is the source code of the Python Program to check whether the number is Neon Number or Not.

Code:

num=int(input("Enter a number:"))
sqr=num*num
#Sum of digit
sum=0
while sqr!=0:
    rem = sqr % 10
    sum += rem
    sqr //= 10

if sum==num:
    print("It is a Neon Number.")
else:
   print("It is not a Neon Number.")

Input/Output:

Enter a number:9                                                                                                                       
It is a Neon Number. 

More:-

C/C++/Java/Python Practice Question