Problem statement:- Program to print series 1,2,8,16,32...n.
Example:
Input: n=35
Output: 1 2 4 8 16 32 /* 1 1*2 2*2 4*2 8*2 16*2 */
Input: n=9
Output: 1 2 4 8 /* 1 1*2 2*2 4*2 */
Data requirement:-
Input Data:- n
Output Data:-i
Program in C
Input Data:- n
Output Data:-i
Program in C
Here is the source code of the C Program to print series 1,2,8,16,32...n.
Code:
#include<stdio.h>
int main()
{
int n,i;
printf("Enter the range of number(Limit):");
scanf("%d",&n);
for(i=1;i<=n;i*=2)
{
printf("%d ",i);
}
}
Enter the range of number(Limit):35
1 2 4 8 16 32
Program in C++
Here is the source code of the C++ Program to print series 1,2,8,16,32...n.
Code:
#include<iostream>
using namespace std;
int main()
{
int n,i;
cout<<"Enter the range of number(Limit):";
cin>>n;
for(i=1;i<=n;i*=2)
{
cout<<i<<" ";
}
}
Enter the range of number(Limit):9
1 2 4 8
Program in Java
Here is the source code of the Java Program to print series 1,2,8,16,32...n.
Code:
import java.util.Scanner;
public class Print_Series {
public static void main(String[] args) {
Scanner sc=new Scanner(System.in);
int n,i;
System.out.printf("Enter the range of number(Limit):");
n=sc.nextInt();
for(i=1;i<=n;i*=2)
{
System.out.print(i+" ");
}
sc.close();
}
}
Enter the range of number(Limit):70
1 2 4 8 16 32 64
Program in Python
Here is the source code of the Python Program to print series 1,2,8,16,32...n.
Code:
n=int(input("Enter the range of number(Limit):"))
i=1
while i<=n:
print(i,end=" ")
i*=2
Enter the range of number(Limit):100
1 2 4 8 16 32 64
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