Convert decimal to binary using recursion

Problem statement:- Program to Convert decimal to binary using recursion.

Data requirement:-

   Input Data:- n

  Output Data:-DecimalToBinary(n)

Program in C

Here is the source code of the C Program to Convert decimal to binary using recursion.

Code:

#include<stdio.h>

int DecimalToBinary(int n)

{

    if(n==0)

        return 0;

    else

        return (n% 2 + 10 * DecimalToBinary(n / 2));

}

int main()

{

    int n;

    printf("Enter the Decimal Value:");

    scanf("%d",&n);

    printf("Binary Value of Decimal number is: %d",DecimalToBinary(n));

}

Input/Output:

Enter the Decimal Value:8

Binary Value of Decimal number is: 1000

Program in C++

Here is the source code of the C++ Program to Convert decimal to binary using recursion.

Code:

#include<iostream>

using namespace std;

int DecimalToBinary(int n)

{

    if(n==0)

        return 0;

    else

        return (n% 2 + 10 * DecimalToBinary(n / 2));

}

int main()

{

    int n;

    cout<<"Enter the Decimal Value:";

    cin>>n;

    cout<<"Binary Value of Decimal number is: "<<DecimalToBinary(n);

}

Input/Output:

Enter the Decimal Value:165

Binary Value of Decimal number is: 10100101

Program in Java

Here is the source code of the Java Program to Convert decimal to binary using recursion.

Code:

import java.util.Scanner;

public class DecimalToBinaryConvert {

static int DecimalToBinary(int n)

{

    if(n==0)

        return 0;

    else

        return (n% 2 + 10 * DecimalToBinary(n / 2));

}

public static void main(String[] args) {

           Scanner cs=new Scanner(System.in);

            int n;

    System.out.print("Enter the Decimal Value:");

    n=cs.nextInt();

    System.out.print("Binary Value of Decimal number is: "+DecimalToBinary(n));

        cs.close();

}

}

Input/Output:

Enter the Decimal Value:10

Binary Value of Decimal number is: 1010

Program in Python

Here is the source code of the Python program to convert decimal to binary using recursion.

Code:

def DecimalToBinary(n):

    if n==0:

        return 0

    else:

        return  (n% 2 + 10 * DecimalToBinary(n // 2))

n=int(input("Enter the Decimal Value:"))

print("Binary Value of Decimal number is:",DecimalToBinary(n))

Input/Output:

Enter the Decimal Value:45

Binary Value of Decimal number is: 101101

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