Problem statement:- Program to Find the reverse of a given number.
Sample Input/Output:-
Sample Input First: 564646 Sample Output First: 646465
Sample Input Second: 7894664 Sample Output Second: 4664987
Data requirement:-
Input Data:- num
Output Data:-num2
Additional Data:-rem
Program in C
Output Data:-num2
Additional Data:-rem
Program in C
Here is the source code of the C Program to find the reverse of a given number.
Code:
#include<stdio.h>
int main()
{
int num;
printf("Enter a number:");
scanf("%d",&num);
int num2=0;
while(num!=0)
{
int rem=num%10;
num/=10;
num2=num2*10+rem;
}
printf("The reverse of the number is %d",num2);
}
Input/Output:
Enter a number:564646
The reverse of the number is 646465
Program in C++
Here is the source code of the C++ Program to find the reverse of a given number.
Code:
#include<iostream>
using namespace std;
int main()
{
int num;
cout<<"Enter a number:";
cin>>num;
int num2=0;
while(num!=0)
{
int rem=num%10;
num/=10;
num2=num2*10+rem;
}
cout<<"The reverse of the number is "<<num2;
}
Input/Output:
Enter a number:7894664
The reverse of the number is 4664987
Program in Java
Here is the source code of the Java Program to find the reverse of a given number.
Code:
import java.util.Scanner;
public class ReverseOfNumber {
public static void main(String[] args) {
Scanner cs=new Scanner(System.in);
int num;
System.out.println("Enter a number:");
num=cs.nextInt();
int num2=0;
while(num!=0)
{
int rem=num%10;
num/=10;
num2=num2*10+rem;
}
System.out.println("The reverse of the number is "+num2);
cs.close();
}
}}
Input/Output:
Enter a number:
7894
The reverse of the number is 4987
Program in Python
Here is the source code of the Python Program to find the reverse of a given number.
Code:
num=int(input("Enter a number:"))
num2=0
while(num!=0):
rem=num%10
num=int(num/10)
num2=num2*10+rem
print("The reverse of the number is",num2)
while(num!=0):
rem=num%10
num=int(num/10)
num2=num2*10+rem
print("The reverse of the number is",num2)
Input/Output:
Enter a number:4589
The reverse of the number is 9854
More Questions:-
More Questions:-
0 Comments
Please do not Enter any spam link in the comment box