Problem statement:- Program to Find the sum of series 1+(1+3)+(1+3+5)+....+N.
Example:
Input: n=5
Output: The sum of the series = 14 /* sum series = 1+(1+3)+(1+3+5)=1+4+9=14*/
Input: n=8
Output: The sum of the series = 30 /* sum series = 1+(1+3)+(1+3+5)+(1+3+5+7)=1+4+9+16=30*/
Data requirement:-
Input Data:- n
Output Data:-sum
Additional Data:- i, j
Program in C
Here is the source code of the C Program to find the sum of series 1+(1+3)+(1+3+5)+....+N.
Code:
#include<stdio.h>
int main()
{
int n,i=1,sum=0,j;
printf("Enter the range of number:");
scanf("%d",&n);
while(i<=n)
{
for(j=1;j<=i;j+=2){
sum+=j;
}
i+=2;
}
printf("The sum of the series = %d",sum);
}int main()
{
int n,i=1,sum=0,j;
printf("Enter the range of number:");
scanf("%d",&n);
while(i<=n)
{
for(j=1;j<=i;j+=2){
sum+=j;
}
i+=2;
}
printf("The sum of the series = %d",sum);
Input/Output:
Enter the range of number:5
The sum of the series = 14
Program in C++
The sum of the series = 14
Program in C++
Here is the source code of the C++ Program to find the sum of series 1+(1+3)+(1+3+5)+.... +N.
Code:
#include<iostream>
using namespace std;
int main()
{
int n,i=1,sum=0,j;
cout<<"Enter the range of number:";
cin>>n;
while(i<=n)
{
for(j=1;j<=i;j+=2){
sum+=j;
}
i+=2;
}
cout<<"The sum of the series = "<<sum;
}
using namespace std;
int main()
{
int n,i=1,sum=0,j;
cout<<"Enter the range of number:";
cin>>n;
while(i<=n)
{
for(j=1;j<=i;j+=2){
sum+=j;
}
i+=2;
}
cout<<"The sum of the series = "<<sum;
}
Input/Output:
Enter the range of number:8
The sum of the series = 30
Program in Java
The sum of the series = 30
Program in Java
Here is the source code of the Java Program to find the sum of series 1+(1+3)+(1+3+5)+.... +N.
Code:
import java.util.Scanner;
public class p25 {
public static void main(String[] args) {
Scanner cs=new Scanner(System.in);
int n,i=1,sum=0,j;
System.out.println("Enter the range of number:");
n=cs.nextInt();
while(i<=n)
{
for(j=1;j<=i;j+=2){
sum+=j;
}
i+=2;
}
System.out.println("The sum of the series = "+sum);
cs.close();
}
}
public class p25 {
public static void main(String[] args) {
Scanner cs=new Scanner(System.in);
int n,i=1,sum=0,j;
System.out.println("Enter the range of number:");
n=cs.nextInt();
while(i<=n)
{
for(j=1;j<=i;j+=2){
sum+=j;
}
i+=2;
}
System.out.println("The sum of the series = "+sum);
cs.close();
}
}
Enter the range of number:
12
The sum of the series = 91
Program in Python
Here is the source code of the Python Program to find the sum of series 1+(1+3)+(1+3+5)+ ....+N.
12
The sum of the series = 91
Program in Python
Here is the source code of the Python Program to find the sum of series 1+(1+3)+(1+3+5)+ ....+N.
Code:
print("Enter the range of number(Limit):")
n = int(input())
i = 1
sum = 0
while (i <= n):
for j in range(1, i + 1,2):
sum+=j
i += 2
print("The sum of the series = ", sum)
n = int(input())
i = 1
sum = 0
while (i <= n):
for j in range(1, i + 1,2):
sum+=j
i += 2
print("The sum of the series = ", sum)
Enter the range of number(Limit):
25
The sum of the series = 819
25
The sum of the series = 819
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