Program to find sum of series 1+4+9+16+25+.....+N

Problem statement:- Program to find the sum of series 1+4+9+16+25+.....+N

 Data requirement:-

   Input Data:- n

  Output Data:- a, b

  Additional Data:- i, k, p

Program in C
  

Here is the source code of the C Program to find the sum of series 1+4+9+16+25+.....+N.

Code:

#include<stdio.h>
#include<math.h>
int main()
{
    int n,sum=0,i;
    printf("Enter the range of number:");
    scanf("%d",&n);

    for(i=1;i<=n;i++)
    {
        sum+=pow(i,2);
    }
    printf("The sum of the series = %d",sum);
}

Input/Output:

Enter the range of number:5
The sum of the series = 55

Program in C++

Here is the source code of the C++ Program to find the sum of series 1+4+9+16+25+.....+N.

Code:

#include<iostream>
#include<cmath>
using namespace std;
int main()
{
    int n,sum=0,i;
    cout<<"Enter the range of number:";
    cin>>n;

    for(i=1;i<=n;i++)
    {
        sum+=pow(i,2);
    }

    cout<<"The sum of the series = "<<sum;
}

Input/Output:

Enter the range of number:12
The sum of the series = 650

Program in Java

Here is the source code of the Java Program to find the sum of series 1+4+9+16+25+.....+N.

Code:

import java.util.Scanner;
public class p31 {

public static void main(String[] args) {
Scanner cs=new Scanner(System.in);
int n,sum=0,i;
    System.out.println("Enter the range of number:");
    n=cs.nextInt();
    for(i=1;i<=n;i++)
    {
        sum+=Math.pow(i,2);
    }
    System.out.println("The sum of the series = "+sum);
     cs.close();
}
}

Input/Output:

Enter the range of number:
15
The sum of the series = 1240

Program in Python

Here is the source code of the Python Program to find the sum of series 1+4+9 +16 +25+ .....+N.

Code:

import math
print("Enter the range of number(Limit):")
n=int(input())
i=1
while(i<=n):
    sum += pow(i, 2)
    i+=1
print("The sum of the series = ",sum)

Input/Output:

Enter the range of number(Limit):
31
The sum of the series =  10416.0

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